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✦ NCF 2023 ALIGNED • CBSE CLASS X ✦

Chapter 5: Arithmetic Progressions

CBSE Official PYQs (2015-2026)

📅 CBSE 2017 (30/1)⭐ 1 Mark📝 MCQ

Q1. If the common difference of an AP is 5, then what is \(a_{18} - a_{13}\)?

(A) 5
(B) 20
(C) 25
(D) 30
Correct Answer: (C) 25
📅 CBSE 2025 (30/1/2)⭐ 1 Mark📝 MCQ

Q2. In an AP, if \(a = 15\), \(d = -3\), \(n = 8\), then the \(n^{\text{th}}\) term \(a_n\) is :

(A) -6
(B) 6
(C) -3
(D) 3
Correct Answer: (A) -6
📅 CBSE 2020 (30/1/1)⭐ 1 Mark📝 MCQ

Q3. The \(11^{\text{th}}\) term of the AP: \(-3, -\frac{1}{2}, 2, \dots\) is :

(A) 28
(B) 22
(C) -38
(D) \(-46\frac{1}{2}\)
Correct Answer: (B) 22
📅 CBSE 2015 (30/3)⭐ 1 Mark📝 MCQ

Q4. Which term of the AP: \(21, 18, 15, \dots\) is \(-81\)?

(A) \(30^{\text{th}}\) term
(B) \(35^{\text{th}}\) term
(C) \(36^{\text{th}}\) term
(D) \(38^{\text{th}}\) term
Correct Answer: (B) \(35^{\text{th}}\) term
📅 CBSE 2020 (30/1/1)⭐ 1 Mark📝 MCQ

Q5. The sum of the first 16 terms of the AP: \(10, 6, 2, \dots\) is :

(A) -320
(B) 320
(C) -352
(D) -400
Correct Answer: (A) -320
📅 CBSE 2015 (30/2)⭐ 1 Mark📝 MCQ

Q6. If the \(p^{\text{th}}\) term of an AP is \(q\) and \(q^{\text{th}}\) term is \(p\), then its \(n^{\text{th}}\) term is :

(A) \(p + q - n\)
(B) \(p + q + n\)
(C) \(p - q + n\)
(D) \(p - q - n\)
Correct Answer: (A) \(p + q - n\)
📅 CBSE 2019 (30/3/1)⭐ 1 Mark📝 MCQ

Q7. If the sum of the first \(n\) terms of an AP is \(3n^2 + n\), then its common difference is :

(A) 3
(B) 6
(C) 4
(D) 9
Correct Answer: (B) 6
📅 CBSE 2024 (30/1/1)⭐ 1 Mark📝 MCQ

Q8. The \(10^{\text{th}}\) term of the AP: \(5, 8, 11, 14, \dots\) is :

(A) 32
(B) 35
(C) 38
(D) 41
Correct Answer: (C) 38
📅 CBSE 2023 (30/3/2)⭐ 1 Mark📝 MCQ

Q9. The common difference of the AP whose \(n^{\text{th}}\) term is \(a_n = 3n + 7\) is :

(A) 7
(B) 3
(C) 10
(D) 1
Correct Answer: (B) 3
📅 CBSE 2018 (30/1)⭐ 1 Mark📝 MCQ

Q10. The next term of the AP: \(\sqrt{7}, \sqrt{28}, \sqrt{63}, \dots\) is :

(A) \(\sqrt{70}\)
(B) \(\sqrt{84}\)
(C) \(\sqrt{97}\)
(D) \(\sqrt{112}\)
Correct Answer: (D) \(\sqrt{112}\)
📅 CBSE 2020 (30/1/1)⭐ 1 Mark📝 MCQ

Q11. The first four terms of an AP whose first term is \(-2\) and common difference is \(-2\) are :

(A) -2, 0, 2, 4
(B) -2, -4, -6, -8
(C) -2, 4, -8, 16
(D) -2, -4, -8, -16
Correct Answer: (B) -2, -4, -6, -8
📅 CBSE 2020 (30/1/1)⭐ 1 Mark📝 MCQ

Q12. If \(k, 2k-1\) and \(2k+1\) are three consecutive terms of an AP, then the value of \(k\) is :

(A) 2
(B) 3
(C) -3
(D) 5
Correct Answer: (B) 3
📅 CBSE 2025 (30/1/1)⭐ 1 Mark📝 MCQ

Q13. In an AP, if \(d = -4\), \(n = 7\), and \(a_n = 4\), then the first term \(a\) is :

(A) 6
(B) 7
(C) 20
(D) 28
Correct Answer: (D) 28
📅 CBSE 2020 (30/1/2)⭐ 1 Mark📝 MCQ

Q14. The list of numbers \(-10, -6, -2, 2, \dots\) is :

(A) an AP with d = -16
(B) an AP with d = 4
(C) an AP with d = -4
(D) not an AP
Correct Answer: (B) an AP with d = 4
📅 CBSE 2022 (30/3/1)⭐ 1 Mark📝 MCQ

Q15. The sum of the first 20 odd natural numbers is :

(A) 100
(B) 200
(C) 400
(D) 420
Correct Answer: (C) 400
📅 CBSE 2024 (30/1/2)⭐ 1 Mark📝 MCQ

Q16. Which term of the AP: \(3, 8, 13, 18, \dots\) is \(78\)?

(A) \(12^{\text{th}}\) term
(B) \(15^{\text{th}}\) term
(C) \(16^{\text{th}}\) term
(D) \(20^{\text{th}}\) term
Correct Answer: (C) \(16^{\text{th}}\) term
📅 CBSE 2023 (30/3/1)⭐ 1 Mark📝 MCQ

Q17. The \(21^{\text{st}}\) term of the AP whose first two terms are \(-3\) and \(4\) is :

(A) 17
(B) 137
(C) 143
(D) -143
Correct Answer: (B) 137
📅 CBSE 2025 (30/1/3)⭐ 1 Mark📝 MCQ

Q18. If the common difference of an AP is \(-4\), and the seventh term (\(a_7\)) is \(4\), then the first term (\(a\)) is :

(A) 4
(B) 20
(C) 24
(D) 28
Correct Answer: (D) 28
📅 CBSE 2021 (30/1)⭐ 1 Mark📝 MCQ

Q19. If the \(n^{\text{th}}\) term of an AP is given by \(a_n = 5 - 3n\), then the sum of its first 10 terms is :

(A) -115
(B) -230
(C) -50
(D) -110
Correct Answer: (A) -115
📅 CBSE 2020 (30/1/1)⭐ 1 Mark📝 MCQ

Q20. The sum of the first five multiples of 3 is :

(A) 45
(B) 55
(C) 65
(D) 75
Correct Answer: (A) 45
📅 CBSE 2024 (30/1/3)⭐ 1 Mark📝 MCQ

Q21. If the \(17^{\text{th}}\) term of an AP exceeds its \(10^{\text{th}}\) term by 7, then the common difference is :

(A) 1
(B) 2
(C) 3
(D) 4
Correct Answer: (A) 1
📅 CBSE 2022 (30/3/2)⭐ 1 Mark📝 MCQ

Q22. For what value of \(p\) are \(2p+1\), \(13\), \(5p-3\) three consecutive terms of an AP?

(A) 2
(B) 4
(C) 3
(D) 5
Correct Answer: (C) 3
📅 CBSE 2026 (30/2/1)⭐ 1 Mark📝 MCQ

Q23. The \(9^{\text{th}}\) term of the AP: \(\frac{1}{m}, \frac{1+m}{m}, \frac{1+2m}{m}, \dots\) is :

(A) \(\frac{1+8m}{m}\)
(B) \(\frac{1+9m}{m}\)
(C) \(\frac{9}{m}\)
(D) \(\frac{8}{m}\)
Correct Answer: (A) \(\frac{1+8m}{m}\)
📅 CBSE 2025 (30/1/1)⭐ 1 Mark📝 MCQ

Q24. The sum of first \(n\) terms of an AP is \(5n - n^2\). The \(n^{\text{th}}\) term of this AP is :

(A) \(5 - 2n\)
(B) \(6 - 2n\)
(C) \(2n - 6\)
(D) \(2n - 5\)
Correct Answer: (B) \(6 - 2n\)
📅 CBSE 2022 (30/2/3)⭐ 1 Mark📝 MCQ

Q25. The first and last terms of an AP are 1 and 11. If the sum of its terms is 36, then the number of terms is :

(A) 5
(B) 6
(C) 7
(D) 8
Correct Answer: (B) 6
📅 CBSE 2020 (30/1/1)⭐ 1 Mark📝 MCQ

Q26. If \(a, b, c\) are in AP, then \(b-a\) is equal to :

(A) \(c-b\)
(B) \(b-c\)
(C) \(a-c\)
(D) \(c-a\)
Correct Answer: (A) \(c-b\)
📅 CBSE 2020 (30/1/3)⭐ 1 Mark📝 MCQ

Q27. Two APs have the same common difference. The first term of one of these is \(-1\) and that of the other is \(-8\). Then the difference between their \(4^{\text{th}}\) terms is :

(A) -1
(B) -8
(C) 7
(D) -9
Correct Answer: (C) 7
📅 CBSE 2023 (30/2/3)⭐ 1 Mark📝 MCQ

Q28. If the common difference of an AP is 3, then \(a_{20} - a_{15}\) is :

(A) 3
(B) 15
(C) 5
(D) 8
Correct Answer: (B) 15
📅 CBSE 2019 (30/1/1)⭐ 1 Mark📝 MCQ

Q29. If 7 times the \(7^{\text{th}}\) term of an AP is equal to 11 times its \(11^{\text{th}}\) term, then its \(18^{\text{th}}\) term is :

(A) 0
(B) 18
(C) 77
(D) 11
Correct Answer: (A) 0
📅 CBSE 2024 (30/1/1)⭐ 1 Mark📝 MCQ

Q30. The sum of the first 100 positive integers is :

(A) 10000
(B) 5050
(C) 5000
(D) 5150
Correct Answer: (B) 5050
📅 CBSE 2024 (30/1/1)⭐ 2 Marks📝 SA-I

Q31. Find the number of terms in the AP: \(7, 13, 19, \dots, 205\).

Solution: 34 terms
📅 CBSE 2019 (30/1/1)⭐ 2 Marks📝 SA-I

Q32. Find the \(20^{\text{th}}\) term from the last term of the AP: \(3, 8, 13, \dots, 253\).

Solution: 158
📅 CBSE 2023 (30/3/2)⭐ 2 Marks📝 SA-I

Q33. How many two-digit numbers are divisible by 3?

Solution: 30 numbers
📅 CBSE 2025 (30/1/2)⭐ 2 Marks📝 SA-I

Q34. If the sum of the first \(n\) terms of an AP is given by \(S_n = 2n^2 + 3n\), find its \(10^{\text{th}}\) term.

Solution: 41
📅 CBSE 2024 (30/1/2)⭐ 2 Marks📝 SA-I

Q35. In an AP, if the \(3^{\text{rd}}\) term is 5 and the \(7^{\text{th}}\) term is 9, find the AP.

Solution: 3, 4, 5, 6, ...
📅 CBSE 2022 (30/3/2)⭐ 2 Marks📝 SA-I

Q36. Find the sum of first 20 terms of an AP whose first term is 5 and common difference is 4.

Solution: 860
📅 CBSE 2017 (30/1)⭐ 2 Marks📝 SA-I

Q37. Which term of the AP: \(121, 117, 113, \dots\) is its first negative term?

Solution: \(32^{\text{nd}}\) term
📅 CBSE 2015 (30/1)⭐ 2 Marks📝 SA-I

Q38. Find the middle term of the AP: \(6, 13, 20, \dots, 216\).

Solution: 111
📅 CBSE 2019 (30/1/2)⭐ 2 Marks📝 SA-I

Q39. If \(S_n\) denotes the sum of first \(n\) terms of an AP, prove that \(S_{12} = 3(S_8 - S_4)\).

Solution: Proof completed algebraically correctly.
📅 CBSE 2023 (30/2/3)⭐ 2 Marks📝 SA-I

Q40. Find the sum of all eleven terms of an AP whose middle term is 30.

Solution: 330
📅 CBSE 2024 (30/1/1)⭐ 3 Marks📝 SA-II

Q41. The sum of the \(4^{\text{th}}\) and \(8^{\text{th}}\) terms of an AP is 24 and the sum of the \(6^{\text{th}}\) and \(10^{\text{th}}\) terms is 44. Find the first three terms of the AP.

Solution: -13, -8, -3
📅 CBSE 2023 (30/3/1)⭐ 3 Marks📝 SA-II

Q42. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first \(n\) terms.

Solution: \(n^2\)
📅 CBSE 2024 (30/1/3)⭐ 3 Marks📝 SA-II

Q43. The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

Solution: \(n = 16\), \(d = 8/3\)
📅 CBSE 2020 (30/1/1)⭐ 3 Marks📝 SA-II

Q44. If the \(m^{\text{th}}\) term of an AP is \(1/n\) and \(n^{\text{th}}\) term is \(1/m\), show that the sum of first \(mn\) terms is \((mn+1)/2\).

Solution: Algebraic proof completed correctly.
📅 CBSE 2018 (30/2)⭐ 3 Marks📝 SA-II

Q45. If the sum of first \(p\) terms of an AP is equal to the sum of its first \(q\) terms (where \(p \neq q\)), then find the sum of its first \((p+q)\) terms.

Solution: 0
📅 CBSE 2022 (30/3/1)⭐ 3 Marks📝 SA-II

Q46. Find the sum of all three-digit natural numbers which are multiples of 7.

Solution: 70,336
📅 CBSE 2016 (30/3)⭐ 3 Marks📝 SA-II

Q47. The sum of the first \(n\) terms of an AP whose first term is 8 and common difference is 20 is equal to the sum of first \(2n\) terms of another AP whose first term is -30 and common difference is 8. Find \(n\).

Solution: \(n = 11\)
📅 CBSE 2020 (30/1/1)⭐ 3 Marks📝 SA-II

Q48. Solve the equation: \(1 + 4 + 7 + 10 + \dots + x = 287\).

Solution: \(x = 40\)
📅 CBSE 2021 (30/1)⭐ 4 Marks📝 Case Study

Q49. Case Study: Monthly Savings Plan
A woman plans to save money for her daughter's higher education. She saves Rs. 2000 in the first month, Rs. 2100 in the second month, Rs. 2200 in the third month, and so on.

Based on the above information, answer the following questions:

  1. Formulate an AP representing her monthly savings and find her savings in the \(24^{\text{th}}\) month. (2 Marks)
  2. Find the total amount saved by her at the end of 2 years (24 months). (2 Marks)
Solution:
1. AP: 2000, 2100, 2200, ...; Savings in 24th month = Rs. 4300
2. Total savings in 24 months = Rs. 75,600
📅 CBSE 2024 (30/2/1)⭐ 5 Marks📝 Case Study

Q50. Case Study: Auditorium Seating Arrangement
In an auditorium, seats are arranged in rows where each row has a fixed number of seats more than the previous row.
- Row 1 has 30 seats
- Row 2 has 34 seats
- Row 3 has 38 seats, and so on...

Based on the above information, answer the following questions:

  1. Formulate an AP representing the seating arrangement and find the common difference. (1 Mark)
  2. Find the number of seats in the \(15^{\text{th}}\) row. (2 Marks)
  3. If there are 1500 total seats in the auditorium, find the total number of rows required. (2 Marks)
Solution:
1. AP: 30, 34, 38, ... ; Common difference d = 4
2. Number of seats in 15th row \(a_{15} = 86\) seats
3. Total 22 rows are required to accommodate 1500 seats.
📅 CBSE 2023 (30/3/1)⭐ 5 Marks📝 Case Study

Q51. Case Study: Potato Race
In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line.

Based on the above information, answer the following questions:

  1. Find the distance run by a competitor to pick up the \(3^{\text{rd}}\) potato and drop it back in the bucket. (2 Marks)
  2. Find the total distance covered by the competitor to collect all the ten potatoes. (3 Marks)
Solution:
1. Distance for 3rd potato = 22 m
2. Total distance covered to collect all ten potatoes = 370 m
📅 CBSE 2024 (30/2/2)⭐ 5 Marks📝 Case Study

Q52. Case Study: Production of TV Sets
A manufacturer of TV sets produced 600 sets in the \(3^{\text{rd}}\) year and 700 sets in the \(7^{\text{th}}\) year. Assuming that the production increases uniformly by a fixed number every year:

Based on the above information, answer the following questions:

  1. Find the production in the \(1^{\text{st}}\) year. (1 Mark)
  2. Find the production in the \(10^{\text{th}}\) year. (2 Marks)
Solution:
1. Production in 1st year = 550 TV sets
2. Production in 10th year = 775 TV sets
3. Total production in 7 years = 4375 TV sets

Live Practice: Chapter 5 Arithmetic Progressions

Q 1
MCQ Score: 0/0