Class 7 Maths Chapter 15 Finding the Unknown Visual Infographic | NCF 2023 Ganita Prakash
Chapter 7: Finding the Unknown
Linear Equations, Balancing Scales, Transposition Rules, and Indian Bījagaṇita Heritage
⚖️ The Balance of Equations
A statement showing equality between two expressions (LHS = RHS). A solution makes LHS exactly equal to RHS.
Perform the exact same operation (add, subtract, multiply, or divide) on both sides to maintain equality.
Addition undoes subtraction; multiplication undoes division (e.g. x − 3 = 5 ⇒ x = 5 + 3).
🔄 Transposition Shortcuts
1. Term Shifting (+ / −):
Moving a term across '=' changes it to its additive inverse (e.g. 2y + 7 = 21 ⇒ 2y = 21 − 7 = 14).
2. Factor Shifting (× / ÷):
A multiplying factor becomes a divisor on the other side (2y = 14 ⇒ y = 14 ÷ 2 = 7). A divisor becomes a multiplier (u/15 = 6 ⇒ u = 6 × 15 = 90).
3. Variables on Both Sides:
Group all variable terms onto one side and all constant numbers onto the other (6y + 7 = 4y + 21 ⇒ 2y = 14).
🏛️ Heritage of Bījagaṇita
Bīja means seed. Just as a grand tree is hidden inside a tiny seed, the answer is hidden inside an unknown number.
Unknowns used color initials: yā (yāvat-tāvat), kā (kālaka = black), nī (nīlaka = blue). Constants used rū (rūpa). Negative numbers were marked with a dot above.
For Ax + B = Cx + D ⇒ x = (D − B) / (A − C).
🧠 Real-World Problem Modeling & Historical Classics
• Fixed + Variable Cost Modeling: Total Expense = (Fixed Delivery/Base Charge) + (Rate × Quantity), e.g. 25p + 50 = 500 or 800 + 20k = 2200.
• Bhāskarāchārya's Horse Problem (1150 CE): Man 1 has ₹300 + 6 horses; Man 2 has 10 horses − ₹100 debt. Equal wealth gives 300 + 6x = 10x − 100 ⇒ 1 horse = ₹100.
• Bakhshālī Manuscript Problem (c. 300 CE): 4 people receive x, 2x, 6x, 24x totaling 132 ⇒ 33x = 132 ⇒ First person gets 4.
• Origin of Word "Algebra": Al-Khwarizmi's 825 CE book Hisab al-jabr wal-muqabala (restoring and balancing) gave the name algebra.
⚠️ Common Algebraic Traps
Trap 1: Distributing Outside Multipliers
In 4(4q + 2) = 50, do NOT subtract 2 first! Expand brackets first to 16q + 8 = 50, or divide the whole side by 4 to get 4q + 2 = 12.5.
Trap 2: Sign Flips in Negative Coefficients
When −5x = 3, dividing by −5 yields x = −3/5, NOT −5/3! Always divide by the exact coefficient with its sign intact.